SOLUTION: x^2 - 60x - 2700 = 0 solve by quadratic formula i.e. D=b^2-4ac x=(-b+/-√(d))÷2a

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Question 952029: x^2 - 60x - 2700 = 0 solve by quadratic formula i.e. D=b^2-4ac
x=(-b+/-√(d))÷2a
Answer by macston(5194) About Me  (Show Source):
You can put this solution on YOUR website!
x%5E2+-+60x+-+2700+=+0
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation ax%5E2%2Bbx%2Bc=0 (in our case 1x%5E2%2B-60x%2B-2700+=+0) has the following solutons:

x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca

For these solutions to exist, the discriminant b%5E2-4ac should not be a negative number.

First, we need to compute the discriminant b%5E2-4ac: b%5E2-4ac=%28-60%29%5E2-4%2A1%2A-2700=14400.

Discriminant d=14400 is greater than zero. That means that there are two solutions: +x%5B12%5D+=+%28--60%2B-sqrt%28+14400+%29%29%2F2%5Ca.

x%5B1%5D+=+%28-%28-60%29%2Bsqrt%28+14400+%29%29%2F2%5C1+=+90
x%5B2%5D+=+%28-%28-60%29-sqrt%28+14400+%29%29%2F2%5C1+=+-30

Quadratic expression 1x%5E2%2B-60x%2B-2700 can be factored:
1x%5E2%2B-60x%2B-2700+=+1%28x-90%29%2A%28x--30%29
Again, the answer is: 90, -30. Here's your graph:
graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B-60%2Ax%2B-2700+%29