SOLUTION: The hypotenuse of a right-angled triangle is (x+8)cm, and the two shorter sides are (x+6)cm and (x-1)cm. Find x

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: The hypotenuse of a right-angled triangle is (x+8)cm, and the two shorter sides are (x+6)cm and (x-1)cm. Find x      Log On


   

Question 951608: The hypotenuse of a right-angled triangle is (x+8)cm, and the two shorter sides are (x+6)cm and (x-1)cm. Find x
Answer by macston(5194) About Me  (Show Source):
You can put this solution on YOUR website!
a=(x+6); b=(x-1); c=(x+8)
a%5E2%2Bb%5E2=c%5E2
%28x%2B6%29%5E2%2B%28x-1%29%5E2=%28x%2B8%29%5E2
x%5E2%2B12x%2B36%2Bx%5E2-2x%2B1=x%5E2%2B16x%2B64
2x%5E2%2B10x%2B37=x%5E2%2B16x%2B64 Subtract x^2 from each side.
x%5E2%2B10x%2B37=16x%2B64 Subtract 10x from each side.
x%5E2%2B37=6x%2B64 Subtract 37 from each side.
x%5E2=27 Find the square root of each side
x=3sqrt%283%29