Question 950135: Write the quadriatic equation below in standard form. Identify the value of a, b, and c.
(3x+2)(x-6)=0
a=
b=
c= Found 3 solutions by amarjeeth123, josgarithmetic, MathTherapy:Answer by amarjeeth123(569) (Show Source):
You can put this solution on YOUR website! (3x+2)(x-6)=0
3x^2-18x+2x-12=0
3x^2-16x-12=0
Comparing with ax^2+bx+c=0 we get
a=3
b=-16
c=-12
You could try to avoid Completing the Square process since your equation is given as factored.
Roots are -2/3 and 6.
Symmetry axis is in the middle. Axis of Symmetry, FOR THE FUNCTION, not just the given equation.
y for the vertex: -----?
Finish by filling in the standard form information. ,
?
You can put this solution on YOUR website!
Write the quadriatic equation below in standard form. Identify the value of a, b, and c.
(3x+2)(x-6)=0
a=
b=