SOLUTION: I'm struggling a lot on solving an equation in quadratic form. The problem I'm currently on is the following: 6(x+2)^4 - 11(x+2)^2 = 4 where u = (x+2)^2 and u^2 = (x+2)^4 So

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: I'm struggling a lot on solving an equation in quadratic form. The problem I'm currently on is the following: 6(x+2)^4 - 11(x+2)^2 = 4 where u = (x+2)^2 and u^2 = (x+2)^4 So       Log On


   



Question 946230: I'm struggling a lot on solving an equation in quadratic form. The problem I'm currently on is the following:
6(x+2)^4 - 11(x+2)^2 = 4
where u = (x+2)^2 and u^2 = (x+2)^4
So far I've done...
6u^2 - 11u + 4 = 0
(2u - 1)(3u - 4) = 0
u = 1/2 and u = 4/3
From there, I need help.

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!

Back substitute,
u=1%2F2
%28x%2B2%29%5E2=1%2F2
x%2B2=0+%2B-+sqrt%281%2F2%29
x=-2+%2B-+sqrt%282%29%2F2
.
.
.
u=4%2F3
%28x%2B2%29%5E2=4%2F3
x%2B2=+0+%2B-+2%2Fsqrt%283%29
x=-2+%2B-+%282%2F3%29sqrt%283%29