SOLUTION: I need help solving these two problems. x^2 – 3x = -6x – 1 x^2 – 10x – 1 = -10

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Question 94606: I need help solving these two problems.
x^2 – 3x = -6x – 1




x^2 – 10x – 1 = -10

Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
X^2-3X=-6X-1
X^2-3X+6X+1=0
X^2+3X+1=0
USING THE QUADRATIC EQUATION:
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
X=(-3+-SQRT[3^2-4*1*1])/2*1
X=(-3+-SQRT[9-4])/2
X=(-3+-SQRT5)/2
X=(-3+-2.236)/2
X=(-3+2.235)/2
X=-.763/2
X=-.382 ANSWER.
X=(-3-2.236)/2
X=-5.236/2
X=-2.618 ANSWER.