Question 943634: A person standing close to the edge on the top of a 195-foot building throws a baseball vertically upward. The quadratic equation
h = -16 t^2 + 128 t + 195
models the ball's height is h , above the ground in feet, t stands for seconds after it was thrown
How high is the ball after 4 seconds?
How many seconds does it take until the ball finally hits the ground? Round to the nearest tenth of a second.
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! f
models the ball's height is h , above the ground in feet, t stands for seconds after it was thrown
How high is the ball after 4 seconds?
Sub 4 for t.
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How many seconds does it take until the ball finally hits the ground? Round to the nearest tenth of a second.
h = -16t^2 + 128t + 195 = 0
Solve for t
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