SOLUTION: Find the vertex and intercepts for each quadratic function, and sketch its graph y = x^2 + 4x y = x^2 + 2x - 24 I have not clue what formula to use. HELP! Thanks i
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-> SOLUTION: Find the vertex and intercepts for each quadratic function, and sketch its graph y = x^2 + 4x y = x^2 + 2x - 24 I have not clue what formula to use. HELP! Thanks i
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Question 9425
:
Find the vertex and intercepts for each quadratic function, and sketch its graph
y = x^2 + 4x
y = x^2 + 2x - 24
I have not clue what formula to use. HELP! Thanks in advance.
Answer by
rapaljer(4671)
(
Show Source
):
You can
put this solution on YOUR website!
y = x^2 + 4x
y = x(x+4) = 0
X-intercepts at x=0 and x= -4
Solved by
pluggable
solver:
SOLVE quadratic equation with variable
Quadratic equation
(in our case
) has the following solutons:
For these solutions to exist, the
discriminant
should not be a negative number.
First, we need to compute the discriminant
:
.
Discriminant d=16 is greater than zero. That means that there are two solutions:
.
Quadratic expression
can be factored:
Again, the answer is: 0, -4. Here's your graph:
y = x^2 + 2x - 24
Y = (x+ 6)(x -4)
X-intercepts at x= -6 and x= 4
Solved by
pluggable
solver:
SOLVE quadratic equation with variable
Quadratic equation
(in our case
) has the following solutons:
For these solutions to exist, the
discriminant
should not be a negative number.
First, we need to compute the discriminant
:
.
Discriminant d=100 is greater than zero. That means that there are two solutions:
.
Quadratic expression
can be factored:
Again, the answer is: 4, -6. Here's your graph:
R^2 at SCC with help from "i from Chicago"