SOLUTION: A trader bought some paraffin for $500. He paid $x for each litre of paraffin. a) Find, in terms of x, an expression for the number of litres he bought. Answer: (500/x)l of p

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: A trader bought some paraffin for $500. He paid $x for each litre of paraffin. a) Find, in terms of x, an expression for the number of litres he bought. Answer: (500/x)l of p      Log On


   



Question 938063: A trader bought some paraffin for $500. He paid $x for each litre of paraffin.
a) Find, in terms of x, an expression for the number of litres he bought.
Answer: (500/x)l of paraffin
b) Due to a leak, he lost 3 litres of paraffin. He sold the remainder of the paraffin for $1 per litre more than he paid for it. Write down and expression, in terms of x, for the sum of money he received.

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
The trader bought +500%2Fx+ liters of paraffin
He lost +3+ liters, so he now has
+500%2Fx+-+3+ liters
---------------------
He originally paid +x+ dollars / liter
He sold for +x%2B+1+ dollars / liter
He received:
+%28+500%2Fx+-+3+%29%2A%28+x+%2B+1+%29+
+500+-+3x+%2B+500%2Fx+-+3+
+500%2Fx+-+3x+%2B+497+
------------------------
check:
suppose +x+=+2+ dollars
He bought +500%2F2+=+250+ liters
He lost +3+ liters and has +247+ liters left
He sold for +3+ dollars/liter
+247%2A3+=+741+ dollars received
and
+500%2Fx+-+3x+%2B+497+
+500%2F2+-+3%2A2+%2B+497+
+250+-+6+%2B+497+=+741+
OK