SOLUTION: What is the solution of 5 = 17x^2 - 200x ?
A. 1 real number
B. 2 complex numbers that are conjugates
C. 2 real unequal numbers
D. 0
E. none of these
Question 936694: What is the solution of 5 = 17x^2 - 200x ?
A. 1 real number
B. 2 complex numbers that are conjugates
C. 2 real unequal numbers
D. 0
E. none of these Found 3 solutions by TimothyLamb, Alan3354, reviewermath:Answer by TimothyLamb(4379) (Show Source):
You can put this solution on YOUR website! 5 = 17x^2 - 200x
17x^2 - 200x - 5 = 0
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the above quadratic equation is in standard form, with a=17, b=-200 and c=-5
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to solve the quadratic equation, by using the quadratic formula, copy and paste this:
17 -200 -5
into this solver: https://sooeet.com/math/quadratic-equation-solver.php
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the quadratic has two real roots at:
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x = 11.789653
x = -0.0249470996
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answer:
C. 2 real unequal numbers
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You can put this solution on YOUR website! What is the solution of 5 = 17x^2 - 200x ?
A. 1 real number
B. 2 complex numbers that are conjugates
C. 2 real unequal numbers
D. 0
E. none of these
Solution:
Express the equation in the form , then identify the values of a, b, and c.
a = 17, b = -200, and c = -5
The discriminant is = 40340 > 0 [positive number]
Therefore, the answer is C. 2 real unequal numbers