SOLUTION: The length of a rectangle is 6 more than two times a number. The width is the number plus three and the area is 32. What is the width of the rectangle?

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Question 929554: The length of a rectangle is 6 more than two times a number. The width is the number plus three and the area is 32. What is the width of the rectangle?

Found 2 solutions by sunny1992, MathTherapy:
Answer by sunny1992(35) About Me  (Show Source):
You can put this solution on YOUR website!
let,
number = X
length = 2x+6
width = x+3
formula of rectangle's area = LxW
given
area= 32
equation
(2x+6)(X+6)=32
solve the equation you will get the answer.

Answer by MathTherapy(10551) About Me  (Show Source):
You can put this solution on YOUR website!

The length of a rectangle is 6 more than two times a number. The width is the number plus three and the area is 32. What is the width of the rectangle?
Let number be N
Then length = 2N + 6, and width = N + 3
Since area = 32, then we get: (2N + 6)(N + 3) = 32
2N%5E2+%2B+12N+%2B+18+=+32 ------- FOILing left side
2N%5E2+%2B+12N+%2B+18+%96+32+=+0
2N%5E2+%2B+12N+-+14+=+0
2%28N%5E2+%2B+6N+-+7%29+=+2%280%29 ------- Factoring out GCF, 2
N%5E2+%2B+6N+-+7+=+0
(N - 1)(N + 7) = 0
N = 1 OR N = - 7 (ignore)
Width: 1 + 3, or highlight_green%284%29 units
You can do the check!!
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