SOLUTION: I am not good at these and I am having some problems Find the x- intercepts y=x^2-5x-10 and y=x^2-4x+4 Thanks you

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Question 92943: I am not good at these and I am having some problems
Find the x- intercepts
y=x^2-5x-10
and y=x^2-4x+4
Thanks you
Answer by venugopalramana(3286) About Me  (Show Source):
You can put this solution on YOUR website!
I am not good at these and I am having some problems
Find the x- intercepts
y=x^2-5x-10
X INTERCEPT MEANS WHERE THE LINE MEETS X AXIS...AT THAT POINT Y COORDINATE=0
HENC
X^2-5X-10=0
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
x+=+%285+%2B-+sqrt%28+%28-5%29%5E2-4%2A1%2A%28-10%29+%29%29%2F%282%2A1%29+
x+=+%285+%2B-+sqrt%28+65+%29%29%2F%282%29+
HENCE X INTERCEPTS ARE
x+=+%285+%2B+sqrt%28+65+%29%29%2F%282%29+
AND
x+=+%285+-+sqrt%28+65+%29%29%2F%282%29+
and y=x^2-4x+4 =0
X^2-2*2X+(2)^2=(X-2)^2=0
HENCE X INTERCEPT IS X=2

Thanks you