Question 92942: I am having problems with these problems
Solve by using the quadratic formula
x^2-x-2=0
and also 4x^2-3x+3=0
Thank you
Answer by jim_thompson5910(35256) (Show Source):
You can put this solution on YOUR website! "Solve by using the quadratic formula
x^2-x-2=0"
Let's use the quadratic formula to solve for x:
Starting with the general quadratic
the general solution using the quadratic equation is:
So lets solve ( notice , , and )
Plug in a=1, b=-1, and c=-2
Negate -1 to get 1
Square -1 to get 1 (note: remember when you square -1, you must square the negative as well. This is because .)
Multiply to get
Combine like terms in the radicand (everything under the square root)
Simplify the square root (note: If you need help with simplifying the square root, check out this solver)
Multiply 2 and 1 to get 2
So now the expression breaks down into two parts
or
Lets look at the first part:
Add the terms in the numerator
Divide
So one answer is
Now lets look at the second part:
Subtract the terms in the numerator
Divide
So another answer is
So our solutions are:
or
Notice when we graph , we get:
and we can see that the roots are and . This verifies our answer
"Solve by using the quadratic formula
4x^2-3x+3=0 "
Let's use the quadratic formula to solve for x:
Starting with the general quadratic
the general solution using the quadratic equation is:
So lets solve ( notice , , and )
Plug in a=4, b=-3, and c=3
Negate -3 to get 3
Square -3 to get 9 (note: remember when you square -3, you must square the negative as well. This is because .)
Multiply to get
Combine like terms in the radicand (everything under the square root)
Simplify the square root (note: If you need help with simplifying the square root, check out this solver)
Multiply 2 and 4 to get 8
After simplifying, the quadratic has roots of
or
Notice if we graph the quadratic , we get
graph of
And we can see that there are no real roots
To visually verify the answer, check out this page to see a visual representation of imaginary roots
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