SOLUTION: x^2+6x+3=0 solve for x using the quadratic formula, write your answer in simplest radical form and also give the answer to the nearest tenth.

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Question 928342: x^2+6x+3=0 solve for x using the quadratic formula, write your answer in simplest radical form and also give the answer to the nearest tenth.
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

x%5E2%2B6x%2B3=0

x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+...in your case a=1, b=6, and c=3

x+=+%28-6+%2B-+sqrt%28+6%5E2-4%2A1%2A3+%29%29%2F%282%2A1%29+

x+=+%28-6+%2B-+sqrt%28+36-12+%29%29%2F2+
x+=+%28-6+%2B-+sqrt%28+24+%29%29%2F2+
x+=+%28-6+%2B-+sqrt%286%2A4+%29%29%2F2+
x+=+%28-6+%2B-+2%2Asqrt%286+%29%29%2F2+
x+=+%28-cross%286%293+%2B-+cross%282%29%2Asqrt%286+%29%29%2Fcross%282%291+
x+=+%28-3+%2B-+sqrt%286+%29%29+
solutions:
x+=+-3+%2B+sqrt%286+%29+
or
x+=+-3-+sqrt%286+%29+