SOLUTION: Hi, I'm struggling with this question on a past paper: A curve has equation y = 2x^2 - x - 1 and a line has equation y = k(2x -3) , where k is a constant. The x-coordinate

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: Hi, I'm struggling with this question on a past paper: A curve has equation y = 2x^2 - x - 1 and a line has equation y = k(2x -3) , where k is a constant. The x-coordinate      Log On


   



Question 927857: Hi, I'm struggling with this question on a past paper:
A curve has equation y = 2x^2 - x - 1 and a line has equation y = k(2x -3) , where
k is a constant.
The x-coordinate of any point of intersection of the curve and the line satisfies the equation
2x^2 - (2k +1)x + 3k - 1 = 0
The curve and the line intersect at two distinct points.
Show that 4k^2 - 20k + 9 > 0.
If someone would be able to explain the steps needed that would be great, as I'm drawing a complete blank on this.
Many thanks,
R

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
We are told that "The curve and the line intersect at two distinct points." so that means 2x%5E2+-%282k+%2B1%29x+%2B+3k-1+=+0 has two distinct roots/solutions for x.


That only happens when the discriminant D is greater than zero, ie D%3E0.


In general, the equation ax%5E2%2Bbx%2Bc+=+0 has the discriminant D+=+b%5E2+-+4ac


For 2x%5E2+-%282k+%2B1%29x+%2B+3k-1+=+0, we see that a+=+2, b+=+-%282k%2B1%29 and c+=+3k-1


Plug in those values of a,b,c and simplify


D+=+b%5E2+-+4ac


D+=+%28-%282k%2B1%29%29%5E2+-+4%2A2%283k-1%29


D+=+%282k%2B1%29%5E2+-+24k+%2B+8


D+=+4k%5E2%2B4k%2B1+-+24k+%2B+8


D+=+4k%5E2-20k%2B9


So because D%3E0 and D+=+4k%5E2-20k%2B9, we know 4k%5E2-20k%2B9%3E0