SOLUTION: Find the slope m and the y-intercept of the graph of the equation. Then graph it. 26x - 13y = 39 slope m = y-intercept (x, y) = ( , )

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: Find the slope m and the y-intercept of the graph of the equation. Then graph it. 26x - 13y = 39 slope m = y-intercept (x, y) = ( , )       Log On


   

Question 926179: Find the slope m and the y-intercept of the graph of the equation. Then graph it.
26x - 13y = 39
slope m =
y-intercept (x, y) = ( , )
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Solve for y.


26x+-+13y+=+39


-13y+=+39-26x


-13y+=+-26x%2B39


y+=+%28-26x%2B39%29%2F%28-13%29


y+=+%28-26x%29%2F%28-13%29%2B%2839%29%2F%28-13%29


y+=+2x-3


Slope is m = 2 and y intercept is b = -3. The y intercept as a point is (0,-3)


Let's graph.


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Looking at y=2x-3 we can see that the equation is in slope-intercept form y=mx%2Bb where the slope is m=2 and the y-intercept is b=-3


Since b=-3 this tells us that the y-intercept is .Remember the y-intercept is the point where the graph intersects with the y-axis

So we have one point




Now since the slope is comprised of the "rise" over the "run" this means
slope=rise%2Frun

Also, because the slope is 2, this means:

rise%2Frun=2%2F1


which shows us that the rise is 2 and the run is 1. This means that to go from point to point, we can go up 2 and over 1



So starting at , go up 2 units


and to the right 1 unit to get to the next point



Now draw a line through these points to graph y=2x-3

So this is the graph of y=2x-3 through the points and
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