You can put this solution on YOUR website! how can I solve and graph this function?
y= (1/2)x^2 - 3x + 3
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One way to do it::
1st:: notice that the coefficient of x^2 is positive so
the parabola open upwards.
2nd:: Find the y-intercept:: f(0) = 0-0+3 = 3 ; so plot (0,3)
3rd:: Find the vertex which occurs at x = -b/(2a) = (3/(2(1/2)) = 3
and f(3) = (1/2)3^2 -9 + 3 = 4.5-9+3 = -4.5+3 = -1.5
So plot the vertex at (3,-1.5)
4th: Draw the parabola opening up from (3,-1.5) and passing thru (0.3).
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Cheers,
Stan H.
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