SOLUTION: I need help with this word problem. It deals with solving quadratic equations by finding square roots. A baseball diamond is actually a square with sides of 90 feet. With Runner

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Question 9225: I need help with this word problem. It deals with solving quadratic equations by finding square roots.
A baseball diamond is actually a square with sides of 90 feet. With Runners on 1st and 2nd, the third baseman fields a ball, runs to third base to get a force out and then throws the ball to first for a double play. Find the length of the third baseman's throw to the nearest foot.

Answer by DWL(56) About Me  (Show Source):
You can put this solution on YOUR website!
This problem is a trigonometry problem using triangles:
It involves the use of Pythagorean Theorem, which says: "In algebraic
terms, a%5E2%2Bb%5E2=c%5E2 where c is the hypotenuse while a and b are the
sides of the triangle.
Think of the basball diamond as a square, and at each base a corner of
the square with each corner being a 90 degree angle. So if we draw a
line from third base to first base we cut the square in half.
We now have two right triangles.
The first leg of the triangle is from first base to second base, the
second leg of the triangle is from second base to third base and the
distance from third base across the field to first base is the hypotenuse.
we can now solve this problem.
Distance from First to Second = 90 Ft., we will call this A
Distance from Second to Third = 90 Ft., We will call this B
Throwing distance from third to First = ?, We will call this C
So we know that A%5E2%2BB%5E2=C%5E2
So we subsitute the numbers we know:
90%5E2%2B90%5E2=C%5E2
So squaring the numbers we get: 8100%2B8100=C%5E2
We then take the square root of both sides to get
sqrt%288100%2B8100%29=C%29
sqrt%2816200%29=C
127.28 = C
So the answer to the nearest Ft. is 127 Feet. Is how far the 3rd. Baseman threw the ball to the fist baseman