SOLUTION: I would appreciate if someone could help me solve: y^2 - 8^(1/2)*y = 18^(1/2)*y -1 Answer is supposed to be y = ( 5*2^(1/2) +/- 46^(1/2) ) / 2

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: I would appreciate if someone could help me solve: y^2 - 8^(1/2)*y = 18^(1/2)*y -1 Answer is supposed to be y = ( 5*2^(1/2) +/- 46^(1/2) ) / 2       Log On


   

Question 921698: I would appreciate if someone could help me solve:
y^2 - 8^(1/2)*y = 18^(1/2)*y -1
Answer is supposed to be y = ( 5*2^(1/2) +/- 46^(1/2) ) / 2
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

y%5E2+-+sqrt%288%29%2Ay+=+sqrt%2818%29%2Ay+-1

y%5E2+-+sqrt%288%29%2Ay+-+sqrt%2818%29%2Ay+%2B1=0

y%5E2+-+%28sqrt%288%29+%2Bsqrt%2818%29%29y+%2B1=0

y%5E2+-+%28sqrt%288%29+%2Bsqrt%2818%29%29y+%2B1=0 ...=>..................


y%5E2+-+5sqrt%282%29y+%2B1=0.......use quadratic formula




x+=+%285sqrt%282%29+%2B-+sqrt%2825%2A2%29-4+%29%29%2F2+

x+=+%285sqrt%282%29+%2B-+sqrt%2850-4+%29%29%2F2+

x+=+%285sqrt%282%29+%2B-+sqrt%2846%29%29%2F2+

x+=+%285sqrt%282%29+%2B-+46%5E%281%2F2%29%29%2F2+