SOLUTION: The height of a projectile, propelled upward with an initial velocity of 40 m/s, is given by the formula h = -4.9t^2 + 40t, where t is the number of seconds after launch. How long

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: The height of a projectile, propelled upward with an initial velocity of 40 m/s, is given by the formula h = -4.9t^2 + 40t, where t is the number of seconds after launch. How long       Log On


   



Question 919094: The height of a projectile, propelled upward with an initial velocity of 40 m/s, is given by the formula h = -4.9t^2 + 40t, where t is the number of seconds after launch. How long after launch will the object be 10 m above the ground?
Answer by Alan3354(69443) About Me  (Show Source):