SOLUTION: 1.)Are the lines a 5x+3y=7 and 3x-5y=8 parallel,perpendicular or neither?

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: 1.)Are the lines a 5x+3y=7 and 3x-5y=8 parallel,perpendicular or neither?      Log On


   

Question 908875: 1.)Are the lines a 5x+3y=7 and 3x-5y=8 parallel,perpendicular or neither?
Found 2 solutions by josgarithmetic, richwmiller:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
REMOVED SOLUTION BECAUSE POSTED CORRECT SOLUTION TO A DIFFERENT QUESTION & DESCRIPTION


------------GOOD SOLUTION---------------

5x%2B3y=7
3y=-5x%2B7
highlight%28y=-%285%2F3%29x%2B7%29
slope is -%285%2F3%29

3x-5y=8
-5y=-3x%2B8
highlight%28y=%283%2F5%29x%2B8%29
slope is 3%2F5

Find the product of the two slopes:
highlight_green%28-%285%2F3%29%283%2F5%29=-1%29
and you can plainly see the slopes are negative reciprocals of each other.
This means the two lines are PERPENDICULAR.

Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
5x+3y=7

-5/3
-a/b=m
3x-5y=8
-3/-5=3/5
perpendicular