SOLUTION: Solve by completing the square: 4x^2 + 2x - 3 = 0 4x^2 + 2x = 3 x^2 + 2/4x = 3/4 Square one-half of the of the x-coefficient and then add it to both sides 1/2 of 2/4 = 1/4^2

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: Solve by completing the square: 4x^2 + 2x - 3 = 0 4x^2 + 2x = 3 x^2 + 2/4x = 3/4 Square one-half of the of the x-coefficient and then add it to both sides 1/2 of 2/4 = 1/4^2       Log On


   

Question 90879This question is from textbook Beginning Algebra
: Solve by completing the square: 4x^2 + 2x - 3 = 0
4x^2 + 2x = 3
x^2 + 2/4x = 3/4
Square one-half of the of the x-coefficient and then add it to both sides
1/2 of 2/4 = 1/4^2 = 1/16
x^2 + 2/4x + 1/16 = 3/4 + 1/16
(x-1/4)^2 = 13/16
x - 1/4 = +/- radical 13 over radical 16
x - 1/4 = +/- radical 13 over 4
x = 1/4 +/- radical 13 over 4
x = 1 +/- radical 13 over 4
Any help is appreciated. This question is from textbook Beginning Algebra

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Solve by completing the square: 4x^2 + 2x - 3 = 0
4x^2 + 2x = 3
x^2 + 2/4x = 3/4
Square one-half of the of the x-coefficient and then add it to both sides
1/2 of 2/4 = 1/4
x^2 + (1/2)x + (1/4)^2 = 3/4 + (1/4)^2
(x-1/4)^2 = 13/16
(x-1/4) = +-[sqrt13]/4
x = [1+sqrt13]/4 or x = [1-sqrt13]/4
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Cheers,
Stan H.