SOLUTION: Determine if the relation is a function. {{{x^2=1+y^2}}}

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Question 90609: Determine if the relation is a function.
x%5E2=1%2By%5E2
Answer by mathispowerful(115) About Me  (Show Source):
You can put this solution on YOUR website!
x%5E2=1%2By%5E2
solve for y:
y = +/-sqrt%28x%5E2-1%29
you can see that for each x value, there will be 2 y values, that means y value
is not unique, according to the definition of function, it is not a function.