SOLUTION: 1.03x^2+2.02x-1.015=0 solve using quadratic formula. I have a=1.03 b=2.02 c=-1.015 and plugged into quad formula and got x= 3.41 and .6267 can you check if i did this ri

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: 1.03x^2+2.02x-1.015=0 solve using quadratic formula. I have a=1.03 b=2.02 c=-1.015 and plugged into quad formula and got x= 3.41 and .6267 can you check if i did this ri      Log On


   

Question 901712: 1.03x^2+2.02x-1.015=0
solve using quadratic formula.
I have a=1.03 b=2.02 c=-1.015
and plugged into quad formula and got x= 3.41 and .6267
can you check if i did this right or was i suppose to do something before setting the a,b,and c using the original equation.
Thanks in advance.
Found 2 solutions by ewatrrr, Theo:
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation ax%5E2%2Bbx%2Bc=0 (in our case 1.03x%5E2%2B2.02x%2B-1.015+=+0) has the following solutons:

x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca

For these solutions to exist, the discriminant b%5E2-4ac should not be a negative number.

First, we need to compute the discriminant b%5E2-4ac: b%5E2-4ac=%282.02%29%5E2-4%2A1.03%2A-1.015=8.2622.

Discriminant d=8.2622 is greater than zero. That means that there are two solutions: +x%5B12%5D+=+%28-2.02%2B-sqrt%28+8.2622+%29%29%2F2%5Ca.

x%5B1%5D+=+%28-%282.02%29%2Bsqrt%28+8.2622+%29%29%2F2%5C1.03+=+0.414759362188684
x%5B2%5D+=+%28-%282.02%29-sqrt%28+8.2622+%29%29%2F2%5C1.03+=+-2.37592441073237

Quadratic expression 1.03x%5E2%2B2.02x%2B-1.015 can be factored:
1.03x%5E2%2B2.02x%2B-1.015+=+1.03%28x-0.414759362188684%29%2A%28x--2.37592441073237%29
Again, the answer is: 0.414759362188684, -2.37592441073237. Here's your graph:
graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1.03%2Ax%5E2%2B2.02%2Ax%2B-1.015+%29

Answer by Theo(13342) About Me  (Show Source):
You can put this solution on YOUR website!
i believe you did it right but i don't believe you got the right answer.

my calculations show that the roots are:

x = -2.376 or x = .415 rounded to 3 decimal places.

a = 1.03
b = 2.02
c = -1.015

x = (-b plus or minus sqrt(b^2-4ac)) / 2a which becomes:

x = (-2.02 plus or minus sqrt(8.2622)) / 2.06 which becomes:

x = (- 2.02 plus or minus 2.8744) / 2.06 which becomes:

x = .415 or x = -2.376 which agrees with what i showed you up above.

i also graphed the equation.

that graph is shown below:

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