SOLUTION: give a possible quadratic equation (in vertex form) with a maximum turning point at (5, -4)

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Question 901188: give a possible quadratic equation (in vertex form) with a maximum turning point at (5, -4)
Answer by reviewermath(1029) About Me  (Show Source):
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Q:
give a possible quadratic equation (in vertex form) with a maximum turning point at (5, -4)
Answer:
The quadratic equation y+=+a%28x-h%29%5E2+%2B+k%29 has a turning point at (h, k).
The turning point is maximum if "a" is negative.
A possible quadratic equation is y+=+-3%28x-5%29%5E2+-+4%29