SOLUTION: X-INTERCEPTS AND VERTEX TO X^2+10X+22

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Question 900106: X-INTERCEPTS AND VERTEX TO X^2+10X+22
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
To get to vertex form, complete the square.
f%28x%29=x%5E2%2B10x%2B22
f%28x%29=x%5E2%2B10x%2B25%2B22-25
f%28x%29=%28x%2B5%29%5E2-3
The vertex is (-5,3).
Now to find the zeros set it equal to zero.
%28x%2B5%29%5E2-3=0
%28x%2B5%29%5E2=3
x%2B5=0+%2B-+sqrt%283%29
x=-5+%2B-+sqrt%283%29
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