SOLUTION: The problem reads: Match the graph with its equation. A) y = –x^2 – 1 B) y = –x^2 + x C) y = –x^2 + 1 D) y = –x^2 + 2x The graph has a downward parabola and the axis loo

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: The problem reads: Match the graph with its equation. A) y = –x^2 – 1 B) y = –x^2 + x C) y = –x^2 + 1 D) y = –x^2 + 2x The graph has a downward parabola and the axis loo      Log On


   

Question 89295: The problem reads:
Match the graph with its equation.

A) y = –x^2 – 1
B) y = –x^2 + x
C) y = –x^2 + 1
D) y = –x^2 + 2x
The graph has a downward parabola and the axis looks like it is at 0, 0.5. Can you please provide an explanation showing all the steps? Thank you.
Answer by Nate(3500) About Me  (Show Source):
You can put this solution on YOUR website!
Vertex: ( -b/(2a), f(x) )
A) y = –x^2 – 1
Vertex: ( 0, -1 )
B) y = –x^2 + x
Vertex: ( 1/2, 1/4 )
C) y = –x^2 + 1
Vertex: ( 0, 1 )
D) y = –x^2 + 2x
Vertex: ( 1, 1 )