SOLUTION: Write x^2-6x+7=0 in the form (x-a)^2=b! where a and b are intergers

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Question 892835: Write x^2-6x+7=0 in the form (x-a)^2=b! where a and b are intergers
Answer by AnlytcPhil(1806) About Me  (Show Source):
You can put this solution on YOUR website!
x%5E2-6x%2B7%22%22=%22%22%220%22

x%5E2-6x%22%22=%22%22-7

Multiply -6 by 1%2F2, get -3
Square -3 get %28-3%29%5E2=%22%22+%2B+9.
Add %22%22%2B9 to both sides:

x%5E2-6x%2B9%22%22=%22%22-7%2B9

Factor the left side, combine terms on right:

%28x-3%29%28x-3%29%22%22=%22%222

Both factors are the same, so write as one of them squared.
Since 2 = 2!, write 2 that way:

%28x-3%29%5E2%22%22=%22%222%21

That's in the form %28x-a%29%5E2%22%22=%22%22b%21, where

a and b are the integers 3 and 2 respetively, and 2 is written as
a factorial 2!.

Edwin