SOLUTION: The quadratic function f(x)= px^2 + qx + r has f(0)= 35,f(1)=20 and f(2)=11.
Find the values of the constants p,q,r.
Express f(x) in the form a(x+b)^2+c. Use your answer to fin
Question 879938: The quadratic function f(x)= px^2 + qx + r has f(0)= 35,f(1)=20 and f(2)=11.
Find the values of the constants p,q,r.
Express f(x) in the form a(x+b)^2+c. Use your answer to find the smallest value of f(x).
The only thing I know is r = 35 (and that was with the help of someone)
please help
thank you Answer by ewatrrr(24785) (Show Source):
Hi
f(x)= px^2 + qx + r has
f(0)= 35, r = 35
f(x)= px^2 + qx + 35
f(1)=20 and f(2)=11
plug and play, substituting first x = 1 and then x = 2
I. 20 = p + q + 35 0r
II. 11 = 4p + 2q + 35 0r
30 = -2p + -2q |Multiplying EQ I by (-2) and ADDING Eqs I & II to eliminate q -24 = 4p + 2q
6 = 2p
3 = p and q = -18
f(x)= 3x^2 -18x + 35
f(x)= 3(x-3)^2 - 27 + 35 completing the Square
f(x)= 3(x-3)^2 +8