SOLUTION: Identify terms for the quadratic formula 0.05b^2-45b-920 for ax^2+bx+c=0 x=-b √b^2-4ac/2a I say that a=0.05 b=-45 c=-920 This is where I am stuck... the solution is 45+&#8

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: Identify terms for the quadratic formula 0.05b^2-45b-920 for ax^2+bx+c=0 x=-b √b^2-4ac/2a I say that a=0.05 b=-45 c=-920 This is where I am stuck... the solution is 45+&#8      Log On


   

Question 878472: Identify terms for the quadratic formula 0.05b^2-45b-920 for ax^2+bx+c=0
x=-b √b^2-4ac/2a
I say that a=0.05 b=-45 c=-920
This is where I am stuck... the solution is 45+√(?)/0.1
Can someone help and give the steps to how you completed(?).
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Instead of 0.05b%5E2-45b-920, I'm going to write 0.05x%5E2-45x-920

For 0.05x%5E2-45x-920, we see a+=+0.05, b+=+-45, c+=+-920

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Use the quadratic formula to solve for x

x+=+%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F%282a%29

x+=+%28-%28-45%29%2B-sqrt%28%28-45%29%5E2-4%280.05%29%28-920%29%29%29%2F%282%280.05%29%29 Plug in a+=+0.05, b+=+-45, c+=+-920

x+=+%2845%2B-sqrt%282025-%28-184%29%29%29%2F%280.1%29

x+=+%2845%2B-sqrt%282025%2B184%29%29%2F%280.1%29

x+=+%2845%2B-sqrt%282209%29%29%2F0.1

x+=+%2845%2Bsqrt%282209%29%29%2F0.1 or x+=+%2845-sqrt%282209%29%29%2F0.1

x+=+%2845%2B47%29%2F0.1 or x+=+%2845-47%29%2F0.1

x+=+92%2F0.1 or x+=+-2%2F0.1

x+=+920 or x+=+-20

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The two solutions are x+=+920 or x+=+-20