SOLUTION: The area of a rectangular garden is 1184 ft2 . The width is 5 ft more than the length. Find the dimensions of the garden.

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Question 876370: The area of a rectangular garden is 1184 ft2 . The width is 5 ft more than the length. Find the dimensions of the garden.
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
A = Lw = x(x+5) = 1184
x^2 + 5x - 1184 = 0 (tossing out negative solution for unit measure)
x = 32ft, the length. width is 37ft
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation ax%5E2%2Bbx%2Bc=0 (in our case 1x%5E2%2B5x%2B-1184+=+0) has the following solutons:

x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca

For these solutions to exist, the discriminant b%5E2-4ac should not be a negative number.

First, we need to compute the discriminant b%5E2-4ac: b%5E2-4ac=%285%29%5E2-4%2A1%2A-1184=4761.

Discriminant d=4761 is greater than zero. That means that there are two solutions: +x%5B12%5D+=+%28-5%2B-sqrt%28+4761+%29%29%2F2%5Ca.

x%5B1%5D+=+%28-%285%29%2Bsqrt%28+4761+%29%29%2F2%5C1+=+32
x%5B2%5D+=+%28-%285%29-sqrt%28+4761+%29%29%2F2%5C1+=+-37

Quadratic expression 1x%5E2%2B5x%2B-1184 can be factored:
1x%5E2%2B5x%2B-1184+=+1%28x-32%29%2A%28x--37%29
Again, the answer is: 32, -37. Here's your graph:
graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B5%2Ax%2B-1184+%29