SOLUTION: 66x^2 + 67x + 10 =0
Solve followig the square root method or the quadratic formula.
Confused on how to work this out any help will be appriciated.
Question 87558: 66x^2 + 67x + 10 =0
Solve followig the square root method or the quadratic formula.
Confused on how to work this out any help will be appriciated. Found 3 solutions by checkley75, rapaljer, stanbon:Answer by checkley75(3666) (Show Source):
You can put this solution on YOUR website! 66x^2+67x+10=0using the quadratic equation we get:
x=(-67+-sqrt[67^2-4*66*10])/2*66
x=(-67+-sqrt[4489-2640])/132
x=(-67+-sqrt[1849])/132
x=(-67+-43)/132
x=(-67+43)/132
x=24/132
x=.18181818 answer.
x=(-67-43)/132
x=110/132
x=.833333 answer.
You can put this solution on YOUR website! This one looks intimidating, when you apply the quadratic formula. Actually, it's not so bad, once you get past the !
a=66, b=67, c=10
or or
Of course, this means that the problem could have been solved by factoring!!
You can put this solution on YOUR website! 66x^2 + 67x + 10 =0
Solve followig the square root method or the quadratic formula.
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If you look at the discriminant you get b^2-4ac = 1849
Then sqrt 1849 = 43
Then (-67+-43)/[2*66]
x = -2/11 or x = -5/6
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Cheers,
Stan H.