SOLUTION: A trader bought paraffin for $500. He paid $x for each litre.
a) Due to a leak he lost 3 litres of paraffin. He sold the remainder for $1 per liter more than he paid for it. Write
Question 872872: A trader bought paraffin for $500. He paid $x for each litre.
a) Due to a leak he lost 3 litres of paraffin. He sold the remainder for $1 per liter more than he paid for it. Write an experession in terms of x for his total income.
B) He made a $20 profit. Write and solve the equation which represents this information.
c) How many litres of paraffin did he sell?
I know that 500/x is the amount of litres he bought, so is the remaining amount. I don't know what to do next, is the remaining amount multiplied by (x+1)? Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! A trader bought paraffin for $500. He paid $x for each litre.
Number of litres he bought = 500/x
a) Due to a leak he lost 3 litres of paraffin.
balance = (500/x) -3
He sold the remainder for $1 per liter more than he paid for it.
= total sales
Profit =
Write an expression in terms of x for his total income.
B) He made a $20 profit.
=20
c) How many litres of paraffin did he sell?
mulyiply by
(500-3x)(x+1) =520x
500x+500-3x^2-3x=520x
3x^2+23x-500=0
solve
a= 3 , b= 23 , c= -500
b^2-4ac= 529 + 6000
b^2-4ac= 6529
x1=( -23 + 80.8 )/ 6
x1= 9.63
x2=( -23 -80.8 ) / 6
x2= -17.30
Ignore negative value
cost per litre = 9.63
that works out to 51.92 litres
he sold 48.92 litres @ 10.63
= 520.02
