SOLUTION: use the given table of values to estimate the volume of the solid formed by revolving y = f(x), {{{0 <= x <= 3}}}, about the x-axis, the table :- ___________ __________

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: use the given table of values to estimate the volume of the solid formed by revolving y = f(x), {{{0 <= x <= 3}}}, about the x-axis, the table :- ___________ __________      Log On


   



Question 872751: use the given table of values to estimate the volume of the solid formed by revolving

y = f(x), 0+%3C=+x+%3C=+3, about the x-axis,
the table :-
_______________________________
x | 0 | 0.5 | 1.0 | 1.5 | 2.0 | 2.5 | 3.0 |
_______________________________
f(x) | 2.3 | 1.4 | 2.9 | 1.1 | 2.4 | 1.6 | 1.9 |

Answer by Edwin McCravy(20055) About Me  (Show Source):
You can put this solution on YOUR website!

Plot the 7 points and connect them:



When we rotate it about the x axis, we'll have a solid figure
with this mid-cross section:



It says just to estimate the volume.  So it may be that your teacher
just wants you to average up those 7 y-values like this:

%282.3+%2B+1.4+%2B+2.9+%2B+1.1+%2B+2.4+%2B+1.6+%2B+1.9%29%2F7 = 1.942857143

and then assume the volume is about the same volume as a cylinder with 
a radius of 1.942857143 like the cylinder which the green lines 
represent a mid-cross section of below:




If that's the kind of estimate your teacher wants, then we
just use the volume of a cylinder with that average y-value
as a its radius.  The cylinder's height h (measured horizontally)
is 3 units,

The formula for the volume of a cylinder is

V = pi%2Ar%5E2%2Ah = pi%2A1.942857143%5E2%2A3 = 35.57565167

So that ought to be a pretty good estimate, about 36 cubic units.

Maybe that's all your teacher wants.

--------------------------------------------

Just for fun, let's find the true volume: and compare:

We'll divide that mid-cross section into 6 little trapezoids:



Each of those trapezoids is a mid cross section of a frustrum of
a cone, with height h, and the right and left radii are the
values of f(x).  The formula for the volume of a frustrum of a
cone is:

V%22%22=%22%22expr%28pi%2Ah%2F3%29%28R%5E2%2BRr%2Br%5E2%29

The height of each one is 1%2F2 so the above will become:

V%22%22=%22%22expr%28pi%2A%281%2F2%29%2F3%29%28R%5E2%2BRr%2Br%5E2%29%22%22=%22%22

V%22%22=%22%22expr%28pi%2F6%29%28R%5E2%2BRr%2Br%5E2%29%22%22=%22%22

Let the volumes of the frustrums of the cones be V1,...,V6

Total volume = V%5B1%5D%2BV%5B2%5D%2BV%5B3%5D%2BV%5B4%5D%2BV%5B5%5D%2BV%5B6%5D

V%5B1%5D%22%22=%22%22expr%28pi%2F6%29%28%282.3%29%5E2%2B%282.3%29%281.4%29%2B%281.4%29%5E2%29%22%22=%22%22expr%28pi%2F6%29%2810.47%29

V%5B2%5D%22%22=%22%22expr%28pi%2F6%29%28%281.4%29%5E2%2B%281.4%29%282.9%29%2B%282.9%29%5E2%29%22%22=%22%22expr%28pi%2F6%29%2814.43%29

V%5B3%5D%22%22=%22%22expr%28pi%2F6%29%28%282.9%29%5E2%2B%282.9%29%281.1%29%2B%281.1%29%5E2%29%22%22=%22%22expr%28pi%2F6%29%2812.81%29 

V%5B4%5D%22%22=%22%22expr%28pi%2F6%29%28%281.1%29%5E2%2B%281.1%29%282.4%29%2B%282.4%29%5E2%29%22%22=%22%22expr%28pi%2F6%29%289.61%29

V%5B5%5D%22%22=%22%22expr%28pi%2F6%29%28%282.4%29%5E2%2B%282.4%29%281.6%29%2B%281.6%29%5E2%29%22%22=%22%22expr%28pi%2F6%29%2812.16%29

V%5B6%5D%22%22=%22%22expr%28pi%2F6%29%28%281.6%29%5E2%2B%281.6%29%281.9%29%2B%281.9%29%5E2%29%22%22=%22%22expr%28pi%2F6%29%289.21%29

Since all are multiplied by pi%2F6

Total volume = V%5B1%5D%2BV%5B2%5D%2BV%5B3%5D%2BV%5B4%5D%2BV%5B5%5D%2BV%5B6%5D%22%22=%22%22

expr%28pi%2F6%29%2810.47%2B14.43%2B12.81%2B9.61%2B12.16%2B9.21%29%29%22%22=%22%22expr%28pi%2F6%29%2A68.69 = 35.9659999

That rounds to 36 cubic units, so the estimate using the cylinder was pretty good.

Edwin