SOLUTION: if the standard for of an equation is y=1/2x^2=x+5, what is the vertex form?

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Question 869358: if the standard for of an equation is y=1/2x^2=x+5, what is the vertex form?
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Not sure if your equation is y=%281%2F2%29x%5E2%2Bx%2B5 or y=%281%2F2%29x%5E2-x%2B5
Complete the square.
y=%281%2F2%29x%5E2%2Bx%2B5
y=%281%2F2%29%28x%5E2%2B2x%2B1%29%2B5-1%2F2
y=%281%2F2%29%28x%2B1%29%5E2%2B9%2F2
Or
y=%281%2F2%29x%5E2-x%2B5
y=%281%2F2%29%28x%5E2-2x%2B1%29%2B5-1%2F2
y=%281%2F2%29%28x-1%29%5E2%2B9%2F2