Please help me with this question:
sketch the graph of the parabola y = 3(x - 2)² - 5
I have tried everyway I can.
You must learn this rule:
The graph of y = a(x - h)² + k
is either a U-shaped graph or an inverted U-shaped graph.
The vertex (turning point is (h,k) and it goes through
(h-1,k+a) and (h+1),k+a)
Plot those three points and draw a U-shaped or inverted
U-shaped graph through those three points:
Using the rule on your equation:
y = 3(x - 2)² - 5
compare to
y = a(x - h)² + k
a = 3, h = 2, k = -5
The vertex (turning point is (h,k) = (2,-5) and it
goes through (h-1,k+a) = (2-1,-5+3) = (1,-2), and
(2+1,-5+3) = (3,-2)
So plot those three points (1,-2), (2,-5) and (3,-2)
Now draw a smooth U-shaped graph through those three points:
Edwin
