SOLUTION: Please help...my original problem is: 2(x-5)^2 = 3. I think the answer is: x= 10 (plus/minus) sq.rt.6 / 2....am I on the right track? Thank you for your help!

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: Please help...my original problem is: 2(x-5)^2 = 3. I think the answer is: x= 10 (plus/minus) sq.rt.6 / 2....am I on the right track? Thank you for your help!       Log On


   

Question 86764: Please help...my original problem is: 2(x-5)^2 = 3.
I think the answer is: x= 10 (plus/minus) sq.rt.6 / 2....am I on the right track?
Thank you for your help!
Answer by bucky(2189) About Me  (Show Source):
You can put this solution on YOUR website!
If you are saying that the answer is:
.
x=%2810%2B-sqrt%286%29%29%2F2
.
You are correct.