SOLUTION: The area of a rectangle is represented by (X^2+10x-56). If the length of the rectangle is (x-4), what would the width be?

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: The area of a rectangle is represented by (X^2+10x-56). If the length of the rectangle is (x-4), what would the width be?      Log On


   

Question 861951: The area of a rectangle is represented by (X^2+10x-56). If the length of the rectangle is (x-4), what would the width be?
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
You understand that for a rectangle, %28length%29%28width%29=area, so you can use this in the form of width=%28area%29%2F%28length%29.