SOLUTION: Which quadratic equation has maximum at (3, 2)? Select one: a. y = - x2 - 6x - 7 b. y = -x2 + 6x - 7 c. y = x2 + 6x - 7 d. y = - x2 - 6x - 7 y = -x2 + 6x + 7

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: Which quadratic equation has maximum at (3, 2)? Select one: a. y = - x2 - 6x - 7 b. y = -x2 + 6x - 7 c. y = x2 + 6x - 7 d. y = - x2 - 6x - 7 y = -x2 + 6x + 7      Log On


   

Question 853115: Which quadratic equation has maximum at (3, 2)?
Select one:
a. y = - x2 - 6x - 7
b. y = -x2 + 6x - 7
c. y = x2 + 6x - 7
d.
y = - x2 - 6x - 7
y = -x2 + 6x + 7
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
completing the Square:
y = -x2 + 6x - 7 = -(x-3)^2 + 9 - 7
y = -(x-3)^2 + 2 is a parabola opening downward from V(3,2), it max point