SOLUTION: How do you solve 2x^2-8=0 using the quadratic formula?

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Question 845134: How do you solve 2x^2-8=0 using the quadratic formula?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
+2x%5E2+-+8+=+0+
+x+=+%28+-b+%2B-+sqrt%28+b%5E2+-+4%2Aa%2Ac+%29%29+%2F+%282%2Aa%29+
+a+=+2+
+b+=+0+
+c+=+-8+
+x+=+%28+-0+%2B-+sqrt%28+0%5E2+-+4%2A2%2A%28-8%29+%29%29+%2F+%282%2A2%29+
+x+=+%28+-0+%2B-+sqrt%28+64+%29%29+%2F+4+
+x+=+8%2F4+
+x+=+2+
and, also:
+x+=+-8%2F4+
+x+=+-2+
Here's a plot showing roots +x+=+2+, and +x+=+-2+
+graph%28+400%2C+400%2C+-5%2C+5%2C+-10%2C+5%2C+2x%5E2+-+8+%29+