SOLUTION: A train travels at a rate of (2x+3) miles per hour. How many miles can it travel at that rate in (x-4) hours?

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: A train travels at a rate of (2x+3) miles per hour. How many miles can it travel at that rate in (x-4) hours?      Log On


   



Question 842428: A train travels at a rate of (2x+3) miles per hour. How many miles can it travel at that rate in (x-4) hours?
Answer by Theo(13342) About Me  (Show Source):
You can put this solution on YOUR website!
the formula is:
rate * time = distance.
since your rate is equal to (2x+3) and your time is equal to (x-4), then the distance traveled will be equal to (2x+3) * (x-4).
you will travel different distances depending on the value of x.
your equation is:
y = (2x+3) * (x-4).
since the rate can't be less than 0 and the time can't be less than 0, then x has to be greater than or equal to 4.
when x = 4, the number of hours you have traveled is 0 and you have traveled 0 miles.
when x = 5, the number of hours you have traveled is 1 and the rate you are traveling at is 5 miles per hour, so you have traveled 5 miles.
you can create a table to capture the different number of hours and the resulting miles per hour and the resulting distance.
the equation for the distance traveled would be:
y = (2x+3) * (x-4).
that graph is shown below:
graph%28600%2C600%2C-5%2C21%2C-100%2C1000%2C%282x%2B3%29%2A%28x-4%29%2C363%29
you can see from the graph that x has to be greater then 4 in order for the distance traveled to be positive.
this graph shows you the number of hours traveled and the distance traveled.
it does not show you the rate of speed.
the number of hours traveled is equal to x-4.
you have to keep that in mind.
x is not the number of hours traveled.
x-4 is.
sometimes a graph is good to see what's happening.
sometimes a table is.
here, a table might be better.
the following table tracks the number of hours traveled and the rate of speed and the distance traveled.
	time	rate	distance
x	x-4	2x+3	(x-4)*(2x+3)
4	0	11	0
5	1	13	13
6	2	15	30
7	3	17	51
8	4	19	76
9	5	21	105
10	6	23	138
11	7	25	175
12	8	27	216
13	9	29	261
14	10	31	310
15	11	33	363
16	12	35	420
17	13	37	481
18	14	39	546
19	15	41	615
20	16	43	688
21	17	45	765
22	18	47	846
23	19	49	931
24	20	51	1020
25	21	53	1113


when x = 15, the table says the distance traveled is 363 miles and the number of hours traveled is 11 and the rate of speed is equal to 33 miles per hour.
the table shows all the figures used.
the graph just shows the value of x and the distance traveled.
you have to translate the value of x to the number of hours traveled by subtracting 4 from it.
in this case, the table is clearer because it gives you all the pertinent data in one shot.

a horizontal line at y = 363 was shown on the graph to highlight the fact that when x = 15, y = 363. this may or may not be easy for you to see. Just look at the intersection point of the horizontal line with the graph and then draw a vertical line down to the x-axis and you will see that the value of x is 15 at that point. It's not all that easy to see. The table is clearer.

The bottom line on your equation is that you don't have enough information to get one answer.
you will get many depending on the value of x.
you would need some other information, such as what is the rate of speed when the car has traveled for 10 hours.
In that case, you will be able to find the distance traveled and the rate of speed.
the answer to that question would be:
when the car travels for 10 hours, the rate of speed is equal to 31 miles per hour and the distance traveled is 310 miles.