Question 842023: 2y^2+4xy=x^2
Solve for y.
I cannot figure out what to even do here
what could the answer be? Found 2 solutions by Alan3354, jim_thompson5910:Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! 2y^2+4xy=x^2
Solve for y.
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2y^2+4xy-x^2 = 0
y = 2x + sqrt(4x^2 + 8x^2)/2
y = 2x + x*sqrt(3)
y = x*(2 + sqrt(3))
y = x*(2 - sqrt(3))