SOLUTION: 3x^2 + 2 1/2 x = -2 A x = {-5 +- i[SQRT(71)}/12 Bx = {5 +- i[SQRT(71)]}/12 Cx = {-2 +- i[SQRT(12)]}/7 Dx = {2 +- i[SQRT(17)]}/-7 E x = {-3 +- i[SQRT(17)]}/12 F x = {3

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: 3x^2 + 2 1/2 x = -2 A x = {-5 +- i[SQRT(71)}/12 Bx = {5 +- i[SQRT(71)]}/12 Cx = {-2 +- i[SQRT(12)]}/7 Dx = {2 +- i[SQRT(17)]}/-7 E x = {-3 +- i[SQRT(17)]}/12 F x = {3       Log On


   



Question 841615: 3x^2 + 2 1/2 x = -2
A x = {-5 +- i[SQRT(71)}/12
Bx = {5 +- i[SQRT(71)]}/12
Cx = {-2 +- i[SQRT(12)]}/7
Dx = {2 +- i[SQRT(17)]}/-7
E x = {-3 +- i[SQRT(17)]}/12
F x = {3 +- i[SQRT(71)]}/-12

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 
Hi,
3x^2 + 2 1/2 x = -2
3x^2 + 2 1/2 x + 2 = 0
3x%5E2+%2B+%285%2F2%29+x+%2B+2+=+0
6x^2 + 5x + 4 = 0 |format: a^2 + bx + c
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
x+=+%28-5+%2B-+i%2Asqrt%28+71+%29%29%2F%2812%29+