SOLUTION: 3x^2 + 2 1/2 x = -2 A x = {-5 +- i[SQRT(71)}/12 Bx = {5 +- i[SQRT(71)]}/12 Cx = {-2 +- i[SQRT(12)]}/7 Dx = {2 +- i[SQRT(17)]}/-7 E x = {-3 +- i[SQRT(17)]}/12 F x = {3
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-> SOLUTION: 3x^2 + 2 1/2 x = -2 A x = {-5 +- i[SQRT(71)}/12 Bx = {5 +- i[SQRT(71)]}/12 Cx = {-2 +- i[SQRT(12)]}/7 Dx = {2 +- i[SQRT(17)]}/-7 E x = {-3 +- i[SQRT(17)]}/12 F x = {3
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Question 841615
:
3x^2 + 2 1/2 x = -2
A x = {-5 +- i[SQRT(71)}/12
Bx = {5 +- i[SQRT(71)]}/12
Cx = {-2 +- i[SQRT(12)]}/7
Dx = {2 +- i[SQRT(17)]}/-7
E x = {-3 +- i[SQRT(17)]}/12
F x = {3 +- i[SQRT(71)]}/-12
Answer by
ewatrrr(24785)
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Hi,
3x^2 + 2 1/2 x = -2
3x^2 + 2 1/2 x + 2 = 0
6x^2 + 5x + 4 = 0 |format: a^2 + bx + c