SOLUTION: Find the standard equation of a parabola that has a vertical axis and satisfies the given conditions. vertex (6, −5), x-intercept −1

 

Hi,

the vertex form of a Parabola opening up(a>0) or down(a<0),  

where(h,k) is the vertex  and  x = h  is the Line of Symmetry

vertex (6, −5), x-intercept −1 , P(-1,0)

   |using P(-1,0) to solve for 'a'

  0 = 49a - 5