SOLUTION: The cable for a suspension bridge is modelled by the equation h = 1/800(x − 200)^2 + 30 where h metres is the distance above the base of the bridge and x metres is the distan

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Question 826011: The cable for a suspension bridge is modelled by the equation h = 1/800(x − 200)^2 + 30 where h metres is the distance above the base of the bridge and x metres is the distance from the left side of the bridge.
Determine the turning point of the graph of the equation.
Determine the suitable values of x.
Determine the range of values of h.
What distance does the cable span?
What is the closest distance of the cable from the base of the bridge?
What is the greatest distance of the cable from the base of the bridge?
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
The cable for a suspension bridge is modeled by the equation
h(x) = (1/800)(x − 200)^2 + 30
graph%28400%2C400%2C-500%2C1000%2C-10%2C250%2C%281%2F800%29%28x-200%29%5E2%2B30%29
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where h metres is the distance above the base of the bridge
and x metres is the distance from the left side of the bridge.
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Determine the turning point of the graph of the equation.
Vertex:: (200,30/800) = (200,0.0375)
Determine the suitable values of x. [0,400]
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Note: h(0) = 80 ft.
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Determine the range of values of h.[0.0375,80]
What distance does the cable span?:: 400 ft
What is the closest distance of the cable from the base of the bridge?:: 0.0375'
What is the greatest distance of the cable from the base of the bridge?:: 80'
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Cheers,
Stan H.
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