SOLUTION: A rocket is launched from atop a 104-foot cliff with an initial velocity of 113 ft/sec.
problem a: Substitute the values into the vertical motion formula
h=-16t(to the power o
Question 82180: A rocket is launched from atop a 104-foot cliff with an initial velocity of 113 ft/sec.
problem a: Substitute the values into the vertical motion formula
h=-16t(to the power of 2)+vt=c. (v is the initial velocity and c is the starting height.) what is h (height) when the rocket hits the ground?
problem b: Use the quadratic formula to find out how long the rocket will take to his the ground after it is launched. Round to the nearest tenth of a second. Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! A rocket is launched from atop a 104-foot cliff with an initial velocity of 113 ft/sec.
problem a: Substitute the values into the vertical motion formula
h=-16t(to the power of 2)+vt=c. (v is the initial velocity and c is the starting height.)
h(t)= -16t^2 + 113t +104
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what is h (height) when the rocket hits the ground?
The height is zero when the rocket hits the round.
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problem b: Use the quadratic formula to find out how long the rocket will take to hit the ground after it is launched. Round to the nearest tenth of a second.
-16t^2 + 113t +104 = 0
t = [-113+-sqrt(113^2-4*-16*104)]/-32
t = [-113+-sqrt19425]/-32
t = [-113+-139.37]/-32
t = 7.88 seconds
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Cheers,
Stan H.
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