Question 814610: x^2+x+1 and 2x^2+8
Find the zeros of each function by using the quadratic formula.
Answer by TimothyLamb(4379)   (Show Source):
You can put this solution on YOUR website! x^2 + x + 1
2x^2 + 8
---
x^2 + x + 1
---
the above quadratic equation is in standard form, with a=1, b=1, and c=1
---
to solve the quadratic equation, plug this:
1 1 1
into this: https://sooeet.com/math/quadratic-equation-solver.php
---
the roots of the quadratic are complex:
-0.5 + (0.866025404)i
-0.5 - (0.866025404)i
---
---
2x^2 + 8
---
the above quadratic equation is in standard form, with a=2, b=0, and c=8
---
to solve the quadratic equation, plug this:
2 0 8
into this: https://sooeet.com/math/quadratic-equation-solver.php
---
the roots of the quadratic are complex:
0 + (2)i
0 - (2)i
---
Solve and graph linear equations:
https://sooeet.com/math/linear-equation-solver.php
---
Solve quadratic equations, quadratic formula:
https://sooeet.com/math/quadratic-formula-solver.php
---
Convert fractions, decimals, and percents:
https://sooeet.com/math/fraction-decimal-percent.php
---
Calculate and graph the linear regression of any data set:
https://sooeet.com/math/linear-regression.php
|
|
|
