Question 812076: use the discriminant to determine the number of real roots of each equation and then solve each equation using the quadratic formula.
2t^2 + 1 = 6t
Answer by TimothyLamb(4379)   (Show Source):
You can put this solution on YOUR website! 2t^2 + 1 = 6t
2t^2 - 6t + 1 = 0
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the above quadratic equation is in standard form, with a=2, b=-6, and c=1
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from the quadratic formula the discriminant is: b^2 - 4ac
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b^2 - 4ac
(-6)^2 - 4(2)(1)
36 - 8 = 28
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Answer 1:
since the discriminant > 0 the function has two real roots
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to solve the above equation using the quadratic formula, plug this:
2 -6 1
into this: https://sooeet.com/math/quadratic-equation-solver.php
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Answer 2:
the roots (solutions) of the above quadratic equation are:
2.82287566
0.177124344
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