SOLUTION: x^2+4x-6 (put into vertex form)--> y=(x-h)^2+k 3x^2+6x-3=0 (solve by using quadratic formula)

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Question 811563: x^2+4x-6 (put into vertex form)--> y=(x-h)^2+k
3x^2+6x-3=0 (solve by using quadratic formula)

Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Use of quadratic formula solution is merely plugging-in values from the given equation.

Putting (the first one) into "vertex" form, or Standard Form, is a different process. Complete The Square!

y=x%5E2%2B4x-6 as given. The missing square term to use is %284%2F2%29%5E2=4.
'
y=%28x%5E2%2B4x%2B4-6-4%29
y=%28%28x%5E2%2B4x%2B4%29-10%29
highlight%28y=%28x%2B2%29%5E2-10%29---------------DONE.