SOLUTION: Hello, I need your help! I got a system of these three equations. 1. 0 =4a+2b+c 2. -2=9a+3b+c 3. -2= a- b+c I don't know how to change those to find out the equation y=a

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: Hello, I need your help! I got a system of these three equations. 1. 0 =4a+2b+c 2. -2=9a+3b+c 3. -2= a- b+c I don't know how to change those to find out the equation y=a      Log On


   

Question 811155: Hello, I need your help!
I got a system of these three equations.
1. 0 =4a+2b+c
2. -2=9a+3b+c
3. -2= a- b+c
I don't know how to change those to find out the equation y=ax^2+bx+c.
Thanks!
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Hello, I need your help!
I got a system of these three equations.
1. 0 =4a+2b+c
2. -2=9a+3b+c
3. -2= a- b+c
I don't know how to change those to find out the equation y=ax^2+bx+c.
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I used my TI-84 to get:
a = -2/3
b = 4/3
c = 0
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Cheers,
Stan H.
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