SOLUTION: Ax^2 +Bx+C=0 Question:this is the standad form of a quadratic, follow the steps for completeing the square and see what you get. I don't even know where to start!!

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Question 80201: Ax^2 +Bx+C=0
Question:this is the standad form of a quadratic, follow the steps for completeing the square and see what you get.
I don't even know where to start!!
Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Starting with:ax%5E2%2Bbx%2Bc+=+0 complete the square and see what results.
ax%5E2%2Bbx%2Bc+=+0 Subtract c from both sides..
ax%5E2%2Bbx+=+-c Next, divide through by a.
x%5E2%2B%28b%2Fa%29x+=+-c%2Fa Now complete the square in the x-terms by adding the square of half the x-coefficient to both sides.. This would be%28b%2F2a%29%5E2+=+b%5E2%2F4a%5E2
x%5E2%2B%28b%2Fa%29x%2Bb%5E2%2F4a%5E2+=+b%5E2%2F4a%5E2-c%2Fa Now factor the left side.
%28x%2Bb%2F2a%29%5E2+=+b%5E2%2F4a%5E2-c%2Fa Simplify the right side.
%28x%2Bb%2F2a%29%5E2+=+%28b%5E2-4ac%29%2F4a%5E2 Now take the square root of both sides.
x%2Bb%2F2a+=+sqrt%28%28b%5E2-4ac%29%2F4a%5E2%29 Simplify.
x%2Bb%2F2a+=+sqrt%28b%5E2-4ac%29%2F2a Finally, subtract b%2F2a from both sides.
x+=+%28-b%2F2a%29%2B-sqrt%28b%5E2-4ac%29%2F2a Simplify.
x+=+%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F2a Does this look familiar?
If you don't recognise it, it's the quadratic formula!